Quote:
Originally Posted by rmath
Race6: First the 3 & 7 are both scratched.
second I listed the 2 & 5 as tied since both had two # 2s.
As a result of the two scratches there were only 5 horses running and all 5 contenders had all 4 ratings. In cases with only 5 horses running I hace found that 85+% of the time the winner has a 2 or lower in the 4 Factors.
Richard
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Sorry about that Dick, I thought I had eliminated all scratches from those races, but I re-assembled and must have missed Race 6
Now, it sounds like you're saying, when comparing
Rank #2s, unlike when comparing
Rank #1s when the PL/BPP #1s outweigh the VDC/CSR Rank #1s, in this case 2 horses with 2 Rank #2s as the 2 and 5 horses have - they should be treated equally (and not the #2 outweighing the #5 because its Rank #2s come from PL/BPP).
Is that correct?
(It is clear why the
1 horse is the next in line (Tier C) and not the 4 horse: it has more Rank #4s compared to the 4 horse's Rank #5s.)
Ted